Question

Can someone help with this

Answer 1

Explanation:

The standard form of a circle is

`(x-h)^2+(y-k)^2=r^2` where h and k are the coordinates of the center of the circle, and r is the radius squared. Our center is located at (-6, -4) and from the center to the outer edge is 2 units, so the radius is 2-squaraed, which is 4. That makes the equation for this circle

`(x-(-6))^2+(y-(-4))^2=4` which simplifies to

`(x+6)^2+(y+4)^2=4`