Question

Two semiconductor materials have exactly the same properties except material A has a bandgap energy of 0.90 eV and material B has a bandgap energy of 1.10 eV. Determine the ratio of

Answer 1

Answer: hello your question is incomplete attached below is the complete question

answer : Ac = 5° , A
`_(f)` = 2.5°

Step-by-step explanation:

Bandgap energy for material A = 0.90 eV

Bandgap energy for material B = 1.10 eV

Calculate the ratio of ni for Material B to Material B

Total derivation ( d ) = d1 + d2

d = A
`_(c)` ( μ
`_(c)` - 1 ) + A
`_(f)` ( μ
`_(f)` - 1 ) ---- ( 1 )

where : d = 1° , μ
`_(c)` = 1.5 , μ
`_(f)` = 1.6

Input values into equation 1 above

1° = 0.5Ac + 0.6Af ---- ( 2 )

also d = d1 [ 1 - w/ w1 ] ------ ( 3 )

∴ d = Ac ( μ
`_(c)` - 1 ) ( 1 - w/w1 )

1° = Ac ( 1.5 - 1 ) ( 1 - 0.06/0.1 ) --- ( 4 )

resolving equation ( 4 )

Ac = 5°

resolving equation ( 2 )

A
`_(f)` = 2.5°