Answer:
0.7627
Explanation:
This is a binomial probability problem
Given :
Number of trials, n = 5
p = number of correct option / total options = 1/4 = 0.25
q = 1 - p = 1 - 0.25 = 0.75
Using the binomial probability relation :
P(x = x) = nCx * p^x * q^(n-x)
Getting atleast 1 correct :
P(x ≥ 1) = p(x = 1) + p(x = 2) + p(x = 3) + p(x =4) + p(x = 5)
P(x =1) = 5C1 * 0.25^1 * 0.75^4 = 0.3955
P(x =2) = 5C2 * 0.25^2 * 0.75^3 = 0.2637
P(x =3) = 5C3 * 0.25^3 * 0.75^2 = 0.0879
P(x =4) = 5C4 * 0.25^4 * 0.75^5 = 0.0146
P(x =5) = 5C5 * 0.25^5 * 0.75^0 = 0.0009
P(x ≥ 1) = 0.3955 + 0.2637 + 0.0879 + 0.0146 + 0.0009 = 0.7627
P(x ≥ 1) = 0.7627