Question

A 92-kg receiver running at 8 m/s catches a pass across the middle and is immediately brought to a stop during a collision with a safety that lasts 0.6 seconds. What was the magnitude of force needed to stop the receiver

Answer 1

Answer:
`1200\ N`

Step-by-step explanation:

Given

Mass of receiver
`m=92\ kg`

Running at a speed of
`v=8\ m/s`

time taken to stop
`t=0.6\ s`

We know, impulse imparted is given by

`\Rightarrow F\cdot dt=m\Delta v\\\Rightarrow F(0.6)=90(8-0)\\\\\Rightarrow F=(90* 8)/(0.6)\\\\\Rightarrow F=1200\ N`

Thus, 1200 N is needed to stop the receiver.