Question

(6,-5) is a point on the terminal side of 0. Find the exact values of cos0, csc0, and tan0.

Answer 1

point (6, -5) => x = 6, y = -5

r =√6² +(-5)² = √(36+25)=√61

the exact value of :

cos 0 = x/r = 6/√61 = 6/61 √61

csc 0 = r/y = √61/(-5) = -1/5 √61

tan 0 = y/x = -5/6

Answer 2

Solutions given:

(6,-5)=(x,y)

r=
`√(6²+(-5)²)=√(61)`

Now

Sin θ=
`(y)/(r)`=
`(-5)/(√(61))`

Cosθ=
`(x)/(r)`=
`(6)/(√(61))`

CSC θ=
`(r)/(y)`=
`(√(61))/(-5)`

Tan θ=θ=
`(y)/(x)`=
`(-5)/(6)`

Note:

p=y

b=x

h=r