Question

Find sec 0, sin 0, and tan 0, where is the angle shown in the figure.

Give exact values, not decimal approximations.

Answer 1

Secθ = 11 / 9.22 or sec33°

Sinθ = 6 / 11 or Sin33°

Tanθ = 6 / 9.22 or Tan33°

θ = 33°

Explanation:

Given:

Hypotenuse = 11 unit

Perpendicular = 6 unit

Find:

Secθ

Sinθ

Tanθ

Computation:

Base = √Hypotenuse² - Perpendicular²

Base = √11² - 6²

Base = √121 - 36

Base = √85

Base = 9.22 unit (Approx.)

Secθ = Hypotenuse / Base

Secθ = 11 / 9.22 or sec33°

Sinθ = Perpendicular / Hypotenuse

Sinθ = 6 / 11 or Sin33°

Tanθ = Perpendicular / Base

Tanθ = 6 / 9.22 or Tan33°

So value of θ = 33°