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Find sec 0, sin 0, and tan 0, where is the angle shown in the figure.

Give exact values, not decimal approximations.

Find sec 0, sin 0, and tan 0, where is the angle shown in the figure. Give exact values-example-1
User Tudmotu
by
6.8k points

1 Answer

3 votes

Answer:

Secθ = 11 / 9.22 or sec33°

Sinθ = 6 / 11 or Sin33°

Tanθ = 6 / 9.22 or Tan33°

θ = 33°

Explanation:

Given:

Hypotenuse = 11 unit

Perpendicular = 6 unit

Find:

Secθ

Sinθ

Tanθ

Computation:

Base = √Hypotenuse² - Perpendicular²

Base = √11² - 6²

Base = √121 - 36

Base = √85

Base = 9.22 unit (Approx.)

Secθ = Hypotenuse / Base

Secθ = 11 / 9.22 or sec33°

Sinθ = Perpendicular / Hypotenuse

Sinθ = 6 / 11 or Sin33°

Tanθ = Perpendicular / Base

Tanθ = 6 / 9.22 or Tan33°

So value of θ = 33°

User Xiangwu
by
6.9k points
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