Question

Help please

A gas in a sealed container has a pressure of 125 kPa at a temperature of 303K. If the temperature in the container is increased to 487K, what is the new pressure?

A 201kpa
B 200kpa
C 400kpa
D 78kpa​

Answer 1

A. 201 kPa

Step-by-step explanation:

We can solve this problem by using Boyle's law, which states:

• P₁T₂ = P₂T₁

Where subscript 1 stands for the initial Pressure and Temperature, while 2 stands for the final conditions. That means that in this case:

• P₁ = 125 kPa

• T₂ = 487 K

• P₂ = ?

• T₁ = 303 K

We input the data:

• 125 kPa * 487 K = P₂ * 303 K

And solve for P₂:

• P₂ = 201 kPa