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Find the cost of painting a cubical block of side length 3.2 cm, if painting costs $5 per cm2.

User Ojosilva
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1 Answer

4 votes

Answer:-


\longrightarrow \sf \$ \: 307.2

Solution:-

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-


\green{ \underline { \boxed{ \sf{Surface \: area \:of \:Cube = 6a^2}}}}

  • where a is side of the cube


\begin{gathered}\\\quad \sf Surface \: area \:of \:Cube = 6*(3.2)^2 \\\end{gathered}


\begin{gathered}\\\implies \quad \sf 6* 3.2*3.2 \\\end{gathered}


\begin{gathered}\\\implies \quad \sf 61.44 cm^2 \\\end{gathered}

Now,


\maltese \sf Cost \:of \:painting \: 1 \: cm² = \$ 5


\sf Cost \: of \: painting \: 61.44 \:cm²=61.44×5


\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2


\leadstoThus it would cost $ 307.2 to paint the entire cubical block.

User Chedine
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