1 Answer

Chedine · Answer 1 · 2023-09-18T20:39:02+0000

$\longrightarrow \sf \$ \: 307.2$

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

$\green{ \underline { \boxed{ \sf{Surface \: area \:of \:Cube = 6a^2}}}}$

$\begin{gathered}\\\quad \sf Surface \: area \:of \:Cube = 6*(3.2)^2 \\\end{gathered}$

$\begin{gathered}\\\implies \quad \sf 6* 3.2*3.2 \\\end{gathered}$

$\begin{gathered}\\\implies \quad \sf 61.44 cm^2 \\\end{gathered}$

Now,

$\maltese \sf Cost \:of \:painting \: 1 \: cm² = \$ 5$

$\sf Cost \: of \: painting \: 61.44 \:cm²=61.44×5$

$\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2$

$\leadsto$ Thus it would cost $ 307.2 to paint the entire cubical block.

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