What is the equation of the line that passes through (-1,-4) and (2,5) A. y+1=3(x+4) B. y+4=-3(x+1) C. y+4=3(x+1) D. y-4=-3(x-1)

Question

asked Dec 11, 2022 78.2k views

2 Answers

Tharindu Kumara · Answer 1 · 2022-12-17T17:35:01+0000

Answer:

C.
y+4=3(x+1)

Explanation:

Hi there!

What we need to know:

All the given equations are in point-slope form:
where m is the slope and the given point is

1) Determine the slope of the line

m=(y_2-y_1)/(x_2-x_1) where the given points are
(x_1,y_1) and
(x_2,y_2)

Plug in the points (-1,-4) and (2,5)

$=(5-(-4))/(2-(-1))\\=(5+4)/(2+1)\\=(9)/(3)\\=3$

Therefore, the slope of the line is 3. Plug this into
y-y_1=m(x-x_1) :

y-y_1=3(x-x_1)

2) Plug the point (-1,-4) into
y-y_1=3(x-x_1)

$y-(-4)=3(x-(-1))\\y+4=3(x+1)$

Therefore, the correct answer is C.

I hope this helps!