Answer:
0.122 = 12.2% probability that the student will have scored greater than 600 points on the quantitative section of the SATs.
Explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2022/formulas/mathematics/college/bnaa16b36eg8ubb4w75g6u0qutzsb68wqa.png)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean score of 501 points, and a standard deviation of 85 points.
This means that
![\mu = 501, \sigma = 85](https://img.qammunity.org/2022/formulas/mathematics/college/qim8j26er72l64vl9ujk679mybvcj1fif1.png)
What is the probability that the student will have scored greater than 600 points on the quantitative section of the SATs?
This is 1 subtracted by the p-value of Z when X = 600. So
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2022/formulas/mathematics/college/bnaa16b36eg8ubb4w75g6u0qutzsb68wqa.png)
![Z = (600 - 501)/(85)](https://img.qammunity.org/2022/formulas/mathematics/college/uee4usfy8gr7snwgppy05vm59x45yaj71e.png)
![Z = 1.165](https://img.qammunity.org/2022/formulas/mathematics/college/qwz3xxy5uib83h0loo6qkx2mtzw35gwrio.png)
has a p-value of 0.878.
1 - 0.878 = 0.122
0.122 = 12.2% probability that the student will have scored greater than 600 points on the quantitative section of the SATs.