182k views
2 votes
Janene is solving the equation log3x324=2. Which exponential equation can she use to solve the problem?

A. 324^2=3x
B. 334^x=2/3
C. (3x)^2=324
D. 3x^2=324

User Sfgroups
by
8.5k points

1 Answer

3 votes

Answer:

Option C: (3*x)^2 = 324

Explanation:

Janene is solving the equation:

Log₃ₓ(324) = 2

First, some rules we need to remember:

Logₙ(x) = Ln(x)/Ln(n)

and:

Ln(x^b) = b*Ln(x)

So we can rewrite our expression as:

Log₃ₓ(324) = Ln(324)/Ln(3*x) = 2

Ln(324) = 2*Ln(3*x)

Now we can use the second property:

Ln(324) = 2*Ln(3*x) = Ln( (3*x)^2 )

The arguments in both sides must be the same thing, then:

324 = (3*x)^2

This is the exponential equation she needs to solve.

Then the correct option is C.

User MichaelJohn
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories