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2 votes
10.

Complete.

y^2 + 15y + 56 = (y + 7)(y + )

A. 8

B. –7

C. –8

D. 7

User Tanzin
by
4.7k points

2 Answers

3 votes

Answer:

I would go with letter B. -7

Explanation:

The two factors of a quadratic equation can be multiplied to form the original equation. Let the missing term be a:

y² + 15y + 56 = (y + 7)(y + a)

y² + 15y + 56 = y² + (7 + a)y + 7a

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Step by Step Solution

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Reformatting the input :

Changes made to your input should not affect the solution:

Step by step solution :

STEP 1 :

Trying to factor by splitting the middle term

1.1 Factoring y2+14y+49

The first term is, y2 its coefficient is 1 .

The middle term is, +14y its coefficient is 14 .

The last term, "the constant", is +49

Step-1 : Multiply the coefficient of the first term by the constant 1 • 49 = 49

Step-2 : Find two factors of 49 whose sum equals the coefficient of the middle term, which is 14 .

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 7 and 7

y2 + 7y + 7y + 49

Step-4 : Add up the first 2 terms, pulling out like factors :

y • (y+7)

Add up the last 2 terms, pulling out common factors :

7 • (y+7)

Step-5 : Add up the four terms of step 4 :

(y+7) • (y+7)

The solution is:

y = -7

The solution is:

y = -14 / 2 = -7

10. Complete. y^2 + 15y + 56 = (y + 7)(y + ) A. 8 B. –7 C. –8 D. 7-example-1
User Rajib Biswas
by
4.9k points
7 votes
The answer to this question is A
User Bertofer
by
4.9k points