Question

External crack of length of 3.0 mm was detected on the surface of the shaft of wind turbine made from 4340 steel. The diameter of the shaft of wind turbine is equal to 32 mm. Assume the shaft is subjected to a maximum load of 50,000 N during operation and the radius of the curvature of the crack is 3 x 10-2 mm. Determine the Fracture toughness KC of the shaft Express your answer in to four significant figures. Do not include the units.

Answer 1

The correct answer is "
`K_c=6.0369 \ MPa√(m)`".

Step-by-step explanation:

Given:

Maximum load,

P = 50,000 N

Crack length,

a = 3mm

or,

= 3×10⁻³ m

Diameter,

d = 32 mm

As we know,

⇒ Maximum stress,
`\sigma=(P)/(A)`

`=(50000)/(((\pi)/(4)* 32^2))`

`=62.20 \ N/mm^2`

Now,

⇒ Fracture tougness,
`K_c=Y \sigma√(\pi a)`

On substituting the values, we get

`=1* 62.20* \sqrt{3.14* 3* 10^(-3)}`

`=6.0369 \ MPa√(m)`