Question

What is the molarity of a solution prepared by dissolving 10.0 grams of NaOH in enough water to make a solution with a total volume of 2.40 liters?

O0.104 M NaOH
O0.201 M NaOH
O0.361 M NaOH
O0.412 M NaOH

Answer 1

Answer: The answer is A O0.104 M NaOH

Step-by-step explanation:

Answer 2

Molecular mass of NaOH is 23 g/mol .

So, number of moles of NaOH is given by :

`n = (10)/(40)\ mole`

Now, we know molarity is given by :

`Molarity = (Number \ of \ moles\ of \ salute)/(Volume ( in \ Liter ) )`

`M = (10)/(40* 2.4) \ M\\\\M = 0.104 \ M`

Hence, this is the required solution.