Answer:
100% of the offspring would be black fur, black eyes (16/16)
Step-by-step explanation:
(Because the info. wasn't included here, I'm assuming black fur and black eyes are dominant, BBEE, to the recessive white fur and red eyes, bbee)
For BBEE x bbee, you'd create a typical dihybrid true-breeding punnett square , where the first top row would be BE , BE, BE , BE , and the vertical/side row would be be, be, be, be.
Cross these alleles as you would typically for any punnett square, and you'd see that all the offpsring would result in BbEe genotypes, which is true of any true-breeding dominant x recessive cross, which always results in the dominant phenotype being 100%.
So...
Black Fur and Black Eyes : 16/16 (100%)
Black Fur and Red Eyes: 0/16
White Fur and Black Eyes: 0/16
White Fur and Red Eyes: 0/16