Question

Need help pls. 100 points

Answer 1

`\\ \sf\longmapsto arc \overset{\sim}{ED}=2(<A)=2(27)=54°`

Now

`\\ \sf\longmapsto arc\overset{\sim}{AE}+arc\overset{\sim}{ED}=180`

`\\ \sf\longmapsto arcc\overset{\sim}{AE}=180-54=126°`

Answer 2

arcAE = 126°

Explanation:

Note that arcAD is a diameter therefore arcAD = 180°. And arcAD = arcAE + arcED

Also note that the inscribed angleEAD intercepts the arcED and according to the inscribed angle theorem,

angleEAD = (1/2)arcED

or

arcED = 2×angleEAD = 2×(27°) = 54°

This means that the arcAE is

arcAE = arcAD - arcED

= 180° - 54°

= 126°