Answer:
775.9 g
Step-by-step explanation:
Step 1: Write the balanced equation
2 Al + 3 Cl₂ ⇒ 2 AlCl₃
Step 2: Calculate the mass corresponding to 157.0 g of Al
The molar mass of Al is 26.98 g/mol.
157.0 g × 1 mol/26.98 g = 5.819 mol
Step 3: Calculate the moles of AlCl₃ produced from 5.819 moles of Al
The molar ratio of Al to AlCl₃ is 2:2. The moles of AlCl₃ produced are 2/2 × 5.819 mol = 5.819 mol.
Step 4: Calculate the mass corresponding to 5.819 moles of AlCl₃
The molar mass of AlCl₃ is 133.34 g/mol.
5.819 mol × 133.34 g = 775.9 g