Answer:
the common difference is 6.
Explanation:
Given;
first term of an AP, a = -7
let the common difference = d
The third term is written as;
T₃ = a + 2d
The eight term is written as;
T₈ = a + 7d
The ratio of the eight term to third term = 7:1
![(T_8)/(T_3) = (7)/(1) = (a+ 7d)/(a + 2d) \\\\7 = (a+ 7d)/(a + 2d)\\\\Recall, a = -7\\\\7 = (-7+ 7d)/(-7 + 2d)\\\\7(-7 + 2d) = -7+ 7d\\\\-49 + 14d = -7 + 7d\\\\14d -7d = -7 + 49\\\\7d = 42\\\\d = (42)/(7) \\\\d = 6](https://img.qammunity.org/2022/formulas/mathematics/high-school/70f891csoylfrj6vuldqk56r6cd5kq06n3.png)
Therefore, the common difference is 6.