Question

Pls helppp

You have 2 bags, bag 1 had 5 green marbles, 6 red marbles, 7 pink
marbles and 3 yellow marbles. bag 2 had 6 green marbles 2 red marbles 3 pink marbles and 8 yellow marbles if you pull one from each what is the probability of getting a pink marble from each bag?

Answer 1

The odds of getting a pink marble from the 1st bag are 7/21, .333 repeating, or approximately 33%.

The odds of getting a pink marble from the 2nd bag are 3/19, .158, or approximately 16%

Explanation:

There are a total of 21 marbles in the first bag, and only 7 pink marbles. This means that when you reach into the bag, your odds are 7 out of 21 to select a pink marble. When divided, this can be changed to a percent or decimal.

There are a total of 19 marbles in the second bag, and only 3 pink marbles. When you reach into this bag, your odds are 3 out of 19 to select a pink marble. You can also divide this to become a percent or decimal.

Probability is often calculated in fraction or decimal form. If I flip a coin the odds of getting tails are 50% percent because there are only two possible outcomes, and tails is one of them. This gives you the fraction 1/2 (one-half), which is 50% when reduced.

Answer 2

The answer is 4/10

Explanation:

If you add all marbles in both bags it equals 40. There are 10 pink marbles in both so 40 / 10 is 4 and the denominator would be 10. 4/10