Answer:
28 and 12 . (QUORA)
Explanation:
Let’s write this down. We are looking for X and Y.
The difference between two numbers is 16: −=16
Three times the larger number is seven times the smaller: ∗3=∗7
So, we need to solve X and Y from these two equations.
If we re-arrange X*3 = Y*7, we get Y = X*3/7.
So, −∗3/7=16 . −∗3/7 is the same as 7∗/7−3∗/7 , or 4∗/7 . So 4∗/7=16−>4∗=7∗16−>=7∗4=28 .
Then we just go back to −=16 , and =28 , gives us 28−=16, or =28–16−>=12 .
So the numbers are 28 and 12.