Question

A 2.0 mL sample of air in a syringe exerts a pressure of 1.02 atm at 22 C. If that syringe is placed into boiling water at 100 C and the pressure in the syringe increases to 1.27 atm, what is the new volume of the air in the syringe?

Answer 1

Answer: The new volume of the air in the syringe is 7.3 mL.

Step-by-step explanation:

Given:
`V_(1)` = 2.0 mL,
`P_(1)` = 1.02 atm,
`T_(1) = 22^(o)C`

`V_(2)` = ?,
`P_(2)` = 1.27 atm,
`T_(2) = 100^(o)C`

Formula used to calculate the new volume in syringe is as follows.

`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))`

Substitute the values into above formula as follows.

`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))\\(1.02 atm * 2.0 mL)/(22^(o)C) = (1.27 atm * V_(1))/(100^(o)C)\\V_(1) = 7.3 mL`

Thus, we can conclude that the new volume of the air in the syringe is 7.3 mL.