We first compute for the moles, n, of the solute sodium carbonate,
N
a
2
C
O
3
, by converting the given 5.30 g of the solute using its molar mass, 105.99 g/mol:
n
=
5.30
g
N
a
2
C
O
3
×
1
m
o
l
N
a
2
C
O
3
105.99
g
N
a
2
C
O
3
=
0.0500
m
o
l
N
a
2
C
O
3