Question

How many H2O molecules are in 183.2 grams of H20 gas?

Answer 1

Answer: There are
`61.24 * 10^(23)` molecules present in 183.2 grams of
`H_(2)O` gas.

Step-by-step explanation:

Given: Mass = 183.2 g

Number of moles is the mass of substance divided by its molar mass.

As molar mass of water is 18 g/mol. Therefore, moles of
`H_(2)O` are calculated as follows.

`Moles = (mass)/(molar mass)\\= (183.2 g)/(18 g/mol)\\= 10.17 mol`

According to the mole concept, there are
`6.022 * 10^(22)` molecules present in one mole of a substance.

Hence, molecules present in 10.17 moles are calculated as follows.

`10.17 mol * 6.022 * 10^(23)\\= 61.24 * 10^(23)`

Thus, we can conclude that there are
`61.24 * 10^(23)` molecules present in 183.2 grams of
`H_(2)O` gas.