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If I initially have a gas at a pressure of 1260 kPa, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 1595 kPa and increase the temperature to…
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If I initially have a gas at a pressure of 1260 kPa, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 1595 kPa and increase the temperature to…
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Jan 2, 2022
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If I initially have a gas at a pressure of 1260 kPa, a volume of 23 liters, and a temperature of 200 K, and
then I raise the pressure to 1595 kPa and increase the temperature to 300 K, what is the new volume of
the gas?
Chemistry
high-school
Alexey Trofimov
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Alexey Trofimov
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P1 x V1 P2 x V2
______ = ________
T1 T2
1260 x 23 / 200 = 144.9
1595x V/300
144.9= 1595x V/300
144.9 x 300/1595 = v
27.25 litres
I think
Roy Chan
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Jan 7, 2022
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Roy Chan
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