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1 vote
If I initially have a gas at a pressure of 1260 kPa, a volume of 23 liters, and a temperature of 200 K, and

then I raise the pressure to 1595 kPa and increase the temperature to 300 K, what is the new volume of
the gas?

1 Answer

3 votes
P1 x V1 P2 x V2
______ = ________
T1 T2

1260 x 23 / 200 = 144.9

1595x V/300

144.9= 1595x V/300
144.9 x 300/1595 = v
27.25 litres
I think
User Roy Chan
by
4.8k points