Answer:
![(a)\ r = 8cm](https://img.qammunity.org/2022/formulas/mathematics/college/pyemh629r9g0p8q0k5mi0r93pyusqkjsee.png)
![(b\ Area = 200.96cm^2](https://img.qammunity.org/2022/formulas/mathematics/college/1eijpe4p0fpx2eecvnp5d0fk2bo6xbd5j9.png)
![(c)\ Volume = 2143.573cm^3](https://img.qammunity.org/2022/formulas/mathematics/college/mhzgbv4vrnoykvoezc7j4udyxxx2ddet6q.png)
Explanation:
The largest cross-section of a sphere is the center.
So, we have:
![A : C = 4 : 1](https://img.qammunity.org/2022/formulas/mathematics/college/prkrqqntgdw8hcsar3mocji5hvsej3nqwv.png)
Where
![A = \pi r^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/azjbdd3ky2b83ypmy74fcs58y2ke45n3eg.png)
![C =2\pi r](https://img.qammunity.org/2022/formulas/mathematics/high-school/ihxpbdzn3xvvapx0bz1oghq5m710rbtopk.png)
Solving (a): The radius
implies that
![\pi r^2 : 2\pi r = 4 : 1](https://img.qammunity.org/2022/formulas/mathematics/college/f6mwihrnhn22wj53s67f3bganni5yqq8hl.png)
Express as fraction
![(\pi r^2 )/( 2\pi r) = (4 )/( 1)](https://img.qammunity.org/2022/formulas/mathematics/college/e3u47fn96asxoc9yfk7jnwi2pknzwu93ft.png)
![(\pi r^2 )/( 2\pi r) = 4](https://img.qammunity.org/2022/formulas/mathematics/college/av7hvn9va0q8e4eejqda7cxh6fpifjmwj8.png)
Divide by
![\pi r](https://img.qammunity.org/2022/formulas/advanced-placement-ap/college/lsine71rzqjdtx8yqzl9gltonevydb35yu.png)
![(r)/( 2) = 4](https://img.qammunity.org/2022/formulas/mathematics/college/2a42n78nyvuvyfhpyuik3vr9j3rfzld8t7.png)
Make r the subject
![r = 4 * 2](https://img.qammunity.org/2022/formulas/mathematics/college/14pem243v3idmgk0n44rdpfpevpu1c8a9f.png)
![r = 8cm](https://img.qammunity.org/2022/formulas/mathematics/college/pwkmios4e4yizx9u9ob5ohfi62hxmzfanu.png)
Solving (b): Area of the largest cross-section.
![Area = \pi r^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/9tsuvlylvfumube5ig269a88gj703y4t2m.png)
![Area = 3.14 *8^2](https://img.qammunity.org/2022/formulas/mathematics/college/d2qi0kaxfn94fsw8yde68fu76padyzbu8g.png)
![Area = 200.96cm^2](https://img.qammunity.org/2022/formulas/mathematics/high-school/te1osa40w8jmsydpwjvtlxnoetaqwlk7q4.png)
Solving (b): Volume of the sphere
![Volume =(4)/(3)\pi r^3](https://img.qammunity.org/2022/formulas/mathematics/college/615hsavapdgrpiqmmzh2qpdwh3iwfd6xbx.png)
![Volume =(4)/(3) * 3.14 * 8^3](https://img.qammunity.org/2022/formulas/mathematics/college/3t46dz99nsg3w7xcarfjva1t4gfms7ztgw.png)
![Volume = 2143.573cm^3](https://img.qammunity.org/2022/formulas/mathematics/college/qcuqbu1bk1qi26ostknpbj4gx6jzt6f20l.png)