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The area of the largest cross section of a sphere and the circumference of the sphere are in the ratio 4:1.

The radius of the sphere is ___cm. The circumference of the sphere is about ___cm. The area of the largest cross section is about____ cm. The volume of the sphere is about ___cm​

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Answer:


(a)\ r = 8cm


(b\ Area = 200.96cm^2


(c)\ Volume = 2143.573cm^3

Explanation:

The largest cross-section of a sphere is the center.

So, we have:


A : C = 4 : 1

Where


A = \pi r^2


C =2\pi r

Solving (a): The radius


A : C = 4 : 1 implies that


\pi r^2 : 2\pi r = 4 : 1

Express as fraction


(\pi r^2 )/( 2\pi r) = (4 )/( 1)


(\pi r^2 )/( 2\pi r) = 4

Divide by
\pi r


(r)/( 2) = 4

Make r the subject


r = 4 * 2


r = 8cm

Solving (b): Area of the largest cross-section.


Area = \pi r^2


Area = 3.14 *8^2


Area = 200.96cm^2

Solving (b): Volume of the sphere


Volume =(4)/(3)\pi r^3


Volume =(4)/(3) * 3.14 * 8^3


Volume = 2143.573cm^3

User Dimitri Danilov
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