Answer:
See solution below
Explanation:
The centre of the circle will be the midpoint of both coordinate
Given the coordinates P(-7, -10) and Q = (3,2)
X = x1+x2/2
X = -7+3/2
X = -4/2
X = -2
Y = y1+y2/2
Y = -10+2/2
Y = -8/2
Y = -4
Hence the centre is at (-2, -4)
The distance between the coordinates will be the diamter
PQ =√(3+7)² + (2+10)²
PQ =√(10)² + (12)²
PQ = √100+144
PQ =√244
radius = √244/2
Get the equation
(x-a)² + (y-b)² = r²
(x -(-2))² + (y-(-4))² = (√244/2)²
(x +2)² + (y+4)² = (244/4)
(x +2)² + (y+4)² = 61
This gives the required equation