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Find the direction angle of -12i - 35j

1 Answer

4 votes

Answer:


\theta=71.07^(\circ)

Explanation:

The given vector is :

v = -12i - 35j

We need to find the angle direction of v.

The general vector is given by :

v = xi+yj

The direction angle is :


\theta=\tan^(-1)((y)/(x))

We have, x = -12 and y = -35

So,


\theta=\tan^(-1)((-35)/(-12))\\\\\theta=71.07^(\circ)

So, the required direction angle is
71.07^(\circ).

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