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Need cos A and tan A asap please

Need cos A and tan A asap please-example-1

2 Answers

3 votes

Answer:

Explanation:

sin A=opposite/hypotenuse=12/37

cos A=adjacent/hypotenuse=35/37

tan A=opposite/adjacent=12/35

User Armentage
by
7.4k points
5 votes

Answer:


\sin A=(12)/(37),\\\\\cos A=(35)/(37),\\\\\tan A=(12)/(35)

Explanation:

In a right triangle only, the sine of an angle is equal to the angle's opposite side divided by the hypotenuse of the triangle. (o/h)

The cosine of the angle is equal to the angle's adjacent side divided by the hypotenuse of the triangle. (a/h)

The tangent of the angle is equal to angle's opposite side divided by the adjacent side. (o/a)

In this case, angle A's opposite side is 12, its adjacent side is 35, and the hypotenuse is 37 (o=12, a=35, h=37).

Thus we have:


\sin A=(12)/(37),\\\\\cos A=(35)/(37),\\\\\tan A=(12)/(35)

User Chinthaka
by
8.2k points

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