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HELP ASAP PLEASE! 100 POINTS!

HELP ASAP PLEASE! 100 POINTS!-example-1
User James Palfrey
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2 Answers

24 votes
24 votes

We will use graphical method to solve it.

The inequalities are

  • y<2/3x
  • y≥-x+2

Graph both

We can see that the solution region is rightwards

The solution is (1.2,0.8)

Option D as the intersection point is ahead 1 unlike option A

HELP ASAP PLEASE! 100 POINTS!-example-1
User Sep
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3.0k points
25 votes
25 votes

Answer:

Given system of inequalities:


\large\begin{cases}y < (2)/(3)x\\y\geq-x+2\end{cases}

When graphing inequalities:

  • < or > = dashed line
  • ≤ or ≥ = solid line
  • < or ≤ = shade below the line
  • > or ≥ = shade above the line


y < (2)/(3)x

The slope of the first inequality is 2/3, therefore at x = 1, y = 2/3.

So the correct line for the first inequality is the dotted line with the shallower slope.

As the relation is < for this inequality, the shading should be below the dotted line.


y\geq-x+2

From inspection of the given graphs, the line of the second inequality (solid line) is the same in all graphs.

As the relation is ≥ for this inequality, the shading should be above the solid line.

Therefore, the only graph that satisfies these conclusions is graph D (attached).

HELP ASAP PLEASE! 100 POINTS!-example-1
User Dien Nguyen
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2.3k points