Question

The work of a student to find the dimensions of a rectangle of area 6 + 8x and width 2 is shown below: Step 1: 6 + 8x Step 2: 2(4) + 2(6x) Step 3: 2(4 + 6x) Step 4: Dimensions of the rectangle are 2 and 4 + 6x In which step did the student first make an error and what is the correct step? (1 point) Question 14 options: 1) Step 3; 2 + (4 + 6x) 2) Step 3; 2 + (4 ⋅ 6x) 3) Step 2; 2(4) + 2(4x) 4) Step 2; 2(3) + 2(4x)

Answer 1

Answer: (4)

Explanation:

At step 2 the student rewrites 6 as 2*(4), and 8x as 2*(6x). This is incireect, since 2*(4) is actually 8, and 2*(6x) is 12x.

The correct way to do it is to rewrite 6 as 2*(3), and rewrite 8x as 2*(4x), which corresponds to the answer option (4)

Answer 2

Explanation:

Hello,

A=Ixw

Step 1:

6+8x

Step 2:

2(3)+2(4x)

Step 3:

2(3+4x)

Step 4:

The dimension of the rectangle are 2 and 3+4x. As a result, Students makes the mistake at Step 2; 2(3)+2(4x). Hope it help!