Question

How many milliliters of a stock solution of 2.00M KNO3 would you need to prepare 150mL of a 0.3M solution?

Answer 1

The answer is "22.5"

Step-by-step explanation:

Concentration:

`M_1= 0.3 \ m \ of\ KNO_3\\\\M_2=2.00\ M\\\\`

Volume:

`V_1=150 \ ml \ of\ KNO_3 \\\\V_2=?`

Using formula:

`M_1V_2=M_2V_2\\\\V_2=(M_1V_1)/(M_2)\\\\`

`=(0.3 * 150)/(2)\\\\=(45)/(2)\\\\=22.5`