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How many milliliters of a stock solution of 2.00M KNO3 would you need to prepare 150mL of a 0.3M solution?

1 Answer

5 votes

Answer:

The answer is "22.5"

Step-by-step explanation:

Concentration:


M_1= 0.3 \ m \ of\ KNO_3\\\\M_2=2.00\ M\\\\

Volume:


V_1=150 \ ml \ of\ KNO_3 \\\\V_2=?

Using formula:


M_1V_2=M_2V_2\\\\V_2=(M_1V_1)/(M_2)\\\\


=(0.3 * 150)/(2)\\\\=(45)/(2)\\\\=22.5

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