Question

A bag contains 8 green M&Ms, 12 blue M&Ms, and 2 orange M&Ms. What is the

probability of choosing a green M&M, eating it, and then choosing a blue M&M?

Please help me this is turn in tomorrow please.

Answer 1

16/77 or about 21%

Explanation:

P(G,B) = 8/22 x 12/21 = 16/77 (simplified)