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A bag contains 8 green M&Ms, 12 blue M&Ms, and 2 orange M&Ms. What is the probability of choosing a green M&M, eating it, and then choosing a blue M&M? Please help me this is turn in tomorrow please.
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A bag contains 8 green M&Ms, 12 blue M&Ms, and 2 orange M&Ms. What is the

probability of choosing a green M&M, eating it, and then choosing a blue M&M?

Please help me this is turn in tomorrow please.

User Teunbrand
by
4.5k points

1 Answer

3 votes

Answer:

16/77 or about 21%

Explanation:

P(G,B) = 8/22 x 12/21 = 16/77 (simplified)

User Rizza
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