Question

In the diagram below, AB = 15, DB = 6, BC = 8, and

mZB = 90°. What is the perimeter of triangle ADC?

Answer 1

B 36

Explanation:

DC^2=6^2+8^2. AD=9cm DB=6cm

DC^2=36+64

DC^2=100

DC=√100

DC=10cm

AC^2=15^2+8^2

AC^2=225+64

AC^2=289

AC=√289

AC=17

P OF TRIANGLE ADC=10+9+17

=36cm