Question

What is the value of cd in the equation 32cd=11cd-42?

a. -1/2
b. 1/2
c. 2
d. -2

Answer 1

32cd = 11 cd − 42 : Subtract 11cd from both sides.

32cd = 11cd − 42
-11cd − 11cd
21c = −42

Divide both sides by 21.
21cd /21 = −42/21

cd = −2

Answer 2

d

Explanation:

Given

32cd = 11cd - 42 ( subtract 11cd from both sides )

21cd = - 42 ( divide both sides by 21 )

cd = - 2 → d