Answer:

Step-by-step explanation:
Given that,
Initial volume, V₁ = 43 L
Initial temperature, T₁ = 225℃ = 498 K
Final volume, V₂ = 20.6 L
We need to find the final temperature. We know that, the relation between volume and temperature is given by :

Put all the values,

So, the final temperature is equal to
.