190k views
2 votes
john and jack divided there math homework.John solved twice as many problems as jack plus 1 more problem how many problems did each boy solve if there are 28 assigned problems?

2 Answers

7 votes

Answer:

John: 19

Jack: 9

Explanation:

User Willert
by
5.2k points
6 votes

Answer:

Jack = 9

John = 19

Explanation:

Let the number that Jack solved = N

Then John solved 2N + 1

So

N + 2N + 1 = 28

3N = 28 - 1

3N = 27

N = 27 / 3 = 9 = number Jack solved

2(9) + 1 = 19 = number John solved

User Pankar
by
5.9k points