2 Answers

Buraky · Answer 1 · 2022-10-11T17:42:23+0000

$y = (1)/(3) {x}^(2) - 3$

Explanation:

The general vertex form of the equation is

$y = a {(x - h)}^(2) + k$

where (h, k) are the coordinates of the vertex and a is a constant. In your case, the vertex is located at (0, -3) so your equation becomes

$y = a {x}^(2) - 3$

To find a, substitute the point (3, 0) into the equation

0 = a(3)^2 - 3 ---> a = 1/3

Therefore, the equation has the form

$y = (1)/(3) {x}^(2) - 3$

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