Answer:
-533.68J
Step-by-step explanation:
Using the formula as follows:
Q = m × c × ∆T
Where;
Q = amount of heat required (Joules)
m = mass of substance (g)
c = specific heat of substance (J/g°C)
∆T = change in temperature (°C)
According to the information provided in this question;
Q = ?
m = 28.3 g
c of iron = 0.449 J/g°C
∆T = 24°C - 66°C = -42°C
Using the formula, Q = m × c × ∆T
Q = 28.3 × 0.449 × (-42)
Q = -533.68
Q = -533.68J
This means that 533.68J is lost to the environment when iron of 28.3g cools from 66°C to 24°C.