Question

In the reaction between copper and silver nitrate, 95.3 g of silver and 82.9g of copper nitrate are produced. How much of each reactant was used?​

Answer 1

Reaction

2AgNO₃ + Cu ⇒ Cu(NO₃)₂ + 2Ag

mol silver (Ag): 95.3 : 108 g/mol = 0.882

mol copper nitrate (Cu(NO₃)₂): 82.9 : 187.5 g/mol = 0.441

mol Ag = 2 x mol Cu(NO₃)₂, so 0.441 being the mole basis of the reactants

mol Cu = 0.441

mass Cu = 0.441 x 63.5 g/mol = 28 g

mol AgNO₃ = 0.882

mass AgNO₃ = 0.882 x 170 g/mol = 149.94 g