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ABC is a triangle, right-angled at A. If AB = 6 and AC = 8, find BC.

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Given :

  • ABC is a right angled triangle at A where AB is 6cm, AC is 8cm.

To Find :

  • BC.

Solution :

  • Let the Base be AB cm, Perpendicular be AC cm and Hypotenuse be BC.

We know that,


\qquad \sf{ \pmb{(Hypotenuse ) {}^(2) = (Base) {}^(2) + (Perpendicular) {}^(2) }}

Substituting the given values in the formula :


\qquad\sf{ \dashrightarrow{ ( BC ) {}^(2) = (AB) {}^(2) + (AC ) {}^(2) }}


\qquad\sf{ \dashrightarrow{ ( BC ) {}^(2) = (6) {}^(2) + (8 ) {}^(2) }}


\qquad\sf{ \dashrightarrow{ ( BC ) {}^(2) = 36 + 64 }}


\qquad\sf{ \dashrightarrow{ ( BC ) {}^(2) = 100 }}


\qquad\sf{ \dashrightarrow{ BC {} = √(100) }}


\qquad\sf{ \dashrightarrow{ BC {} = 10 }}

  • Therefore, BC = 10 cm

ABC is a triangle, right-angled at A. If AB = 6 and AC = 8, find BC.-example-1
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