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42 votes
42 votes
2, 10, 50, … Find the sum of the first 6 terms

2, 10, 50, … Find the sum of the first 6 terms-example-1
User Dimple
by
2.5k points

2 Answers

5 votes
5 votes

Answer: 7812

Explanation:

Just did the assignment

User Mervin
by
2.7k points
14 votes
14 votes

Answer:

2+10+50+250+1250+6250=7812

Explanation:

since the common difference is ×5 the progression is a geometric progression

Sum of term of a geometric progression is

Sn = [a{(r^n) - 1}]÷{(r^n)-1} for r>1

Sn = [a{1-(r^n)}]÷{1-(r^n)} for r<1

a is first term =2

r is common difference =5

n is number of terms = 6

Sn sum of terms to n

Sn =2(5⁶-1) ÷(5-1) since r>1

Sn = 7812

User KirillC
by
2.7k points