Solution :
Given :
External diameter of the hemispherical shell, D = 500 mm
Thickness, t = 20 mm
Internal diameter, d = D - 2t
= 500 - 2(20)
= 460 mm
So, internal radius, r = 230 mm
= 0.23 m
Density of molten metal, ρ =
![$7.2 \ g/cm^3$](https://img.qammunity.org/2022/formulas/engineering/college/nefwuub07b02pxr5ovx8lz8twgvan75vkk.png)
=
![$7200 \ kg/m^3$](https://img.qammunity.org/2022/formulas/engineering/college/s9rlsfhypoe4rpgsamchx8le4pq98rb56i.png)
The height of pouring cavity above parting surface is h = 300 mm
= 0.3 m
So, the metallostatic thrust on the upper mold at the end of casting is :
![$F=\rho g A h$](https://img.qammunity.org/2022/formulas/engineering/college/x3karl5io9umx95vyz1v96z3e03qsd0gbw.png)
Area, A
![$=2 \pi r^2$](https://img.qammunity.org/2022/formulas/engineering/college/gl18id3vye47h0g6eip3klyll3mdzhcd4h.png)
![$=2 \pi (0.23)^2$](https://img.qammunity.org/2022/formulas/engineering/college/i1ha6mgipemuaay06tjnpk1z94fq1b2ntl.png)
![$=0.3324 \ m^2$](https://img.qammunity.org/2022/formulas/engineering/college/cif41edgxchafr2dasyozmsaqzv6q6puzh.png)
![$F=\rho g A h$](https://img.qammunity.org/2022/formulas/engineering/college/x3karl5io9umx95vyz1v96z3e03qsd0gbw.png)
![$=7200 * 9.81 * 0.3324 * 0.3$](https://img.qammunity.org/2022/formulas/engineering/college/41qq6ggakn2ikuaf0fa0hfn2lqvogdfz2c.png)
= 7043.42 N