Question

Determine the hydraulic conductivity of a confined aquifer from which water is being pumped by a fully penetrating well. The aquifer is 100 ft thick and the well is being pumped at a rate of 1500 gpm. Water surface in two observation wells 700 ft and 70 ft from the pumped well are respectively 1 ft and 10 ft below their levels prior to the beginning of pumping.

Answer 1

Hydraulic conductivity = 878.53 gpd / ft^2

Step-by-step explanation:

Calculate the hydraulic conductivity of the confined aquifer

Thickness of aquifer ( b ) = 100 ft

Pump rate ( Q ) = 1500 gpm

r₂ = 700 ft

r₁ = 70 ft

h1 = 1 ft , h2 = 10 ft

To determine the hydraulic conductivity we will apply the relation below

Q = 2πKb (( h2 - h1) / In(r₂ / r₁ ) )

1500 = 2 * π * k * 100 (( -1 -(- 10 ) / In ( 700 / 70 ) )

∴ K ( hydraulic conductivity ) = [ 1500 / (( 9 / 2.30 ) ] / 2π*100

= 383.33 / 628.32

K = 0.610087 gpm /ft^2

= 878.53 gpd / ft^2