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What is the mean absolute deviation of the data: 3, 7, 8, 12, 16, 18 of each number. I tried to take a picture but it is too blurry. But pls hurry hurry!!!​

User Filly
by
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1 Answer

1 vote

Answer:


M = 4.67

Explanation:

Given


Data: 3, 7, 8, 12, 16, 18

Required

The mean absolute deviation

Start by calculating the mean


\bar x = (\sum x)/(n)


\bar x = (3+ 7+ 8+ 12+ 16+ 18)/(6)


\bar x = (64)/(6)


\bar x = 10.67

The mean absolute deviation is then calculated using:


M = (1)/(n)\sum\limits^n_(i=1)|x _i - \bar x|

So, we have:


M = (1)/(6)(|3 - 10.67| +|7 - 10.67| + |8 - 10.67| + |12 - 10.67| + |16 - 10.67| + |18 - 10.67|)


M = (1)/(6)(|-7.67| +|- 3.67| + |-2.67| + |1.33| + |5.33| + |7.33|)

Remove absolute brackets


M = (1)/(6)(7.67 +3.67 + 2.67 + 1.33 + 5.33 + 7.33)


M = (1)/(6)*28


M = 4.67

User Reinaldo Chaves
by
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